A3 Mania Forum

Prove the Following Identities
0=1
and 2/10=2
Engineers come on
Koi karle to bolna

If a = 0,

means a^2 - a = 0 also, as a = 0

=> a(a-1) = 0
=> a - 1 = 0
=> a = 1

=> 0 = 1 (as a = 0 from step 1 and a =1 from last step)

2/10 = two/ten
T is canceled with T

From our alphabets we know that,

w=23,
o=15,
e=5,
n=14.

hence.

w and o = 23+15=38
and
e and n = 5+14=19

Therefore wo/en=38/19= 2.

Prooved

too long
we know 0!=1
and 1!=1
so 0=1

! means factorial which we get in permutation
and 2/10
gw is correct in tht bt take small numbers
w=2 o=2 e=2 n=1
so eqn becomes 2*2/2*1=2
We Engineering Aspirants Can Prove Anything

GhostWalker wrote:If a = 0,

means a^2 - a = 0 also, as a = 0

=> a(a-1) = 0
=> a - 1 = 0
=> a = 1

=> 0 = 1 (as a = 0 from step 1 and a =1 from last step)

Prooved

As u can see the highlighted part......

we know that a = 0,

thus, a(a-1) = 0
=>0(0-1) = 0

which contradicts ur EQUATION.....

and yea lol people might think ur rite if they dont take care of ur equation.....

In the second one u just cannot take any number u want like u did, it doesn't make sense that way, coz i can also say then let 2 = x and 10 = y

and let x also = 2 any also y = 1 hence 2/10 = 2! LOL

In the alphabets w is the 23rd alphabet 0 is the 15th, e is the 5th and n is the 14th. Thats how i came up with those numbers.


And in the 1st one u have to add the factorial sign in your proof to make them both equal, but in ur question u said proove 1 = 0 not 1! = 0!, it says PROOVE 1 = 0. What u did shows that 1! = 1 and 0! = 1 not 0 = 1. Look at the proof i showed, it shows 0 = 1 by showing a = a (1 = 0).

You failed in ur own question 2 times LOLX

LOL.....

BTW... he should mention, applying FACTORIAL on both the sides..... ;P

Pain wrote:]If a = 0,

means a^2 - a = 0 also, as a = 0

=> a(a-1) = 0
=> a - 1 = 0
=> a = 1

=> 0 = 1 (as a = 0 from step 1 and a =1 from last step)

Prooved

As u can see the highlighted part......

we know that a = 0,

thus, a(a-1) = 0
=>0(0-1) = 0

which contradicts ur EQUATION.....

and yea lol people might think ur rite if they dont take care of ur equation.....

a(a-1)=0
a-1=0/a
a-1=0
a=1

This shud help u understand it more clearly! LOL!

The 1st step just shows that a^2 - a = 0. as a = 0 => 0^2 - 0 = 0.
Then simple math is used to show that a also = 1 by simplifying that equation.

I nvr substitute a = 0 back in the equation till the last step.

GhostWalker wrote:
a(a-1)=0
a-1=0/a
a-1=0
a=1

This shud help u understand it more clearly! LOL!

The 1st step just shows that a^2 - a = 0. as a = 0 => 0^2 - 0 = 0.
Then simple math is used to show that a also = 1 by simplifying that equation.

I nvr substitute a = 0 back in the equation till the last step.

LOL... thats an illusive trick to prove what u actually showed above.....

BUt in reality.... on the very 1st step.... we know that a = 0, thus,

a(a-1)=0

0(0-1)=0

hence the above equation Contradicts ur Given Statement

, multiply both sides with negative sign then hahaha, -(-1) = -0

hence again 1 = 0

RofL.......

0 is neither negative nor positive number.......... Basic maths........ fool others

1!=0! then dividing both sides by factorial

oooo... which engg r yu pursuing jax?

m inn 12th nw will do aerospace

*Head Spinning* .... i guess ive entered the Jerk Community !

Indian airspace in jeopardy